How do you factor $9a^2 - 64b^2$ ?

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Answer 1 · 2015-05-21T04:22:12

The answer is $9a^2-64b^2=(3a+8b)(3a-8b)$

Problem: $9a^2-64b^2$ .

This expression fits the pattern of the difference of squares:

$a^2-b^2=(a+b)(a-b)$

$a=3a$
$b=8b$

$9a^2-64b^2=(3a+8b)(3a-8b)$

How do you factor 9a^2 - 64b^29a^2 - 64b^2?