Question

How do you factor `27x^3-8y^3`?

Answer 1

`27x^3-8y^3=(3x-2y)(9x^2+6xy+4y^2)`

Explanation:

`27x^3-8y^3=3^3x^3-2^3y^3`
`a^3-b^3=(a-b)(a^2+ab+b^2)`
`3x=a" "2y=b`
`27x^3-8y^3=(3x-2y)(9x^2+6xy+4y^2)`