How do you factor $27x^3-8y^3$ ?

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Answer 1 · 2016-03-07T17:43:41

$27x^3-8y^3=(3x-2y)(9x^2+6xy+4y^2)$

$27x^3-8y^3=3^3x^3-2^3y^3$
$a^3-b^3=(a-b)(a^2+ab+b^2)$
$3x=a" "2y=b$
$27x^3-8y^3=(3x-2y)(9x^2+6xy+4y^2)$

How do you factor 27x^3-8y^327x^3-8y^3?