How do you factor y= 8m^2 - 41m - 42?

3 Answers
Dec 27, 2015

Find a suitable splitting of the middle term, then factor by grouping to find:

8m^2-41m-42=(8m+7)(m-6)

Explanation:

Find a pair of factors of AC = 8*42 = 16*21 = 336 which differ by B=41

The split of 336 into a pair of factors must put all of the powers of 2 on one side, since the difference (41) is odd. If both factors were even, then the difference would be even too.

That leads to the following possibilities to consider:

16xx21

bb (48xx7)

112xx3

336xx1

Having found the pair 48, 7 use that to split the middle term and factor by grouping:

8m^2-41m-42

=8m^2-48m+7m-42

=(8m^2-48m)+(7m-42)

=8m(m-6)+7(m-6)

=(8m+7)(m-6)

Dec 27, 2015

y=(8x+7)(x-6)

Explanation:

You could look for values p, q, r, s such that
color(white)("XXX")pxxr=8
color(white)("XXX")qxxs=-42
color(white)("XXX")ps+qr=-41
(perhaps using the AC method)

...but unless you get lucky, there are quite a few factorings possible.

As an alternative you could use the quadratic formula:
color(white)("XXX")(-b+-sqrt(b^2-4ac))/(2a)

The numbers involved are still ugly but if you use a calculator or spreadsheet (evaluating only the + of the +-)
you should get:
color(white)("XXX")x=6 as a zero for this expression.

Therefore one of the factors will be:
color(white)("XXX")(x-6)
Simple division (8x^2divx=8) and ((-42)div(-6))=+7)
gives the other term:
color(white)("XXX")(8x+7)

Dec 27, 2015

Alternatively, complete the square to find:

8m^2-41m-42 = (m-6)(8m+7)

Explanation:

Alternatively, you can complete the square to proceed directly to the answer as follows:

8m^2-41m-42

=8(m^2-41/8 m - 21/4)

=8(m^2-41/8 m + (41/16)^2 - (41/16)^2 - 21/4)

=8((m-41/16)^2 - 1681/256 - 1344/256)

=8((m-41/16)^2 - 3025/256)

=8((m-41/16)^2 - (55/16)^2)

=8((m-41/16) - 55/16)((m-41/16) + 55/16)

=8(m-96/16)(m+14/16)

=8(m-6)(m+7/8)

=(m-6)(8m+7)

...using the difference of squares identity:

a^2-b^2 = (a-b)(a+b)

with a = m-41/16 and b = 55/16

Ouch!