Question

How do you factor `3y-6x+4xy-2y^2`, by grouping ?

Answer 1

`(y-2x)(3-2y)`

Explanation:

`=color(red)(3)(y-2x)color(red)(-2y)(y-2x)larrcolor(blue)"by grouping"`

`"take out the "color(blue)"common factor "(y-2x)`

`=(y-2x)(color(red)(3-2y))`

`rArr3y-6x+4xy-2y^2=(y-2x)(3-2y)`