How do you solve #25x ^ { 2} - 68= 32#?

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Answer 1 · 2016-12-14T09:05:40

See explanation.

First we move #-68# to the right side:

#25x^2=32+68#

#25x^2=100#

Now we can divide both sides by #25#

#x^2=4#

Now we can say that The solution is:#x=-2# or #x=2#