How do you factor $125x^3-64y^3$ ?

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Answer 1 · 2016-10-04T23:59:40

This is the difference of two cubes,
ie $X^3-Y^3 = (X-Y)(X^2+XY+Y^2)$ (Learn This)

$125x^3−64y^3=(5x)^3-(4y)^3$
$=(5x-4y)((5x)^2+(5x)(4y)+(4y)^2)$
$=(5x-4y)(25x^2+20xy+16y^2)$

How do you factor 125x^3-64y^3 125x^3-64y^3 ?