How do you factor $x^4-y^4$ ?

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Answer 1 · 2016-07-28T19:42:01

$=(x^2+y^2)(x+y)((x-y)$

Since formula $a^2-b^2=(a+b)(a-b)$ can be applied here.
$x^4-y^4$
$=(x^2)^2-(y^2)^2$
$=(x^2+y^2)(x^2-y^2)$
$=(x^2+y^2)(x+y)((x-y)$

How do you factor x^4-y^4x^4-y^4?