How do you factor 3a^2-18a+273a2−18a+27? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Deepak G. Aug 7, 2016 =3(a-3)(a-3)=3(a−3)(a−3) Explanation: 3a^2-18a+273a2−18a+27 =3(a^2-6a+9)=3(a2−6a+9) =3(a^2-2a(3)+3^2)=3(a2−2a(3)+32) =3(a-3)^2=3(a−3)2 =3(a-3)(a-3)=3(a−3)(a−3) Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor x^3 -8x3−8? What are the factors of x^3y^6 – 64? How do you know if x^2 + 10x + 25 is a perfect square? How do you write 16x^2 – 48x + 36 as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor 16x^2-36 using the difference of squares? How do you factor 2x^4y^2-32? How do you factor x^2 - 27? See all questions in Factor Polynomials Using Special Products Impact of this question 2287 views around the world You can reuse this answer Creative Commons License