How do you factor $x^6/8-y^3/27$ ?

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Answer 1 · 2015-05-23T03:08:47

Use the identity: a^3 - b^3 = (a - b) (a^2 + ab + b^2)

Let $x^2 = X,$ then

$(X/2)^3 - (y/3)^3$ = $(X - y)(X^2 + Xy + y^2)$ =

= $(x^2 - y)(x^4 + x^2y + y^2)$

How do you factor x^6/8-y^3/27x^6/8-y^3/27?