Question

How do you factor `27x^3 - 8`?

Answer 1

`(3x-2)(9x^2+6x+4)`

Explanation:

`27x^3-8" is a "color(blue)"difference of cubes"`

`•color(white)(x)a^3-b^3=(a-b)(a^2+ab+b^2)`

`"here "a=3xto(3x)^3=27x^3`

`"and "b=2to(2)^3=8`

`rArr27x^3-8=(3x-2)(9x^2+6x+4)`