How do you simplify $(d^{2}) - 4$ $(d^2)-4$ ?

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Answer 1 · 2015-05-03T12:13:30

We know that $a^{2} - b^{2} = (a + b) (a - b)$ $color(blue)(a^2 - b^2 = (a+b)(a-b)$

And $d^{2} - 4 = d^{2} - 2^{2}$ $d^2 - 4 = d^2 - 2^2$

Using the identity, we can write $d^{2} - 2^{2}$ $d^2 - 2^2$ as $(d + 2) (d - 2)$ $color(green)((d+2)(d-2)$

How do you simplify (d^2)-4(d2)−4(d^2)-4?