How do you evaluate v^ { - 2} \cdot v \cdot 2u ^ { 2} v ^ { - 2}? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Barney V. Mar 8, 2017 (2u^2)/v^3 Explanation: v^-2*v*2u^2v^-2 :.v^-2*v^1*2u^2v^-2 :.v^(-2+1-2)*2u^2 :.v^-3*2u^2 :.1/v^3*(2u^2)/1 :.(2u^2)/v^3 Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor x^3 -8? What are the factors of x^3y^6 – 64? How do you know if x^2 + 10x + 25 is a perfect square? How do you write 16x^2 – 48x + 36 as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor 16x^2-36 using the difference of squares? How do you factor 2x^4y^2-32? How do you factor x^2 - 27? See all questions in Factor Polynomials Using Special Products Impact of this question 1431 views around the world You can reuse this answer Creative Commons License