Question #3828f

Question

Question #3828f

1 Answer

Impact of this question

1478 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-17T15:28:07

See below.

Explanation:

$a x^{2} + b x + c = a (x^{2} + \frac{b}{a} x + \frac{c}{a})$ $a x^2+bx+c = a(x^2+b/ax+c/a)$

and now

$x = \frac{1}{2} ⎛ ⎝ - \frac{b}{a} \pm \sqrt{{(\frac{b}{a})}^{2} - 4 (\frac{c}{a})} ⎞ ⎠$ $x =1/2 (-b/apm sqrt((b/a)^2-4(c/a)))$

or

$a x^{2} + b x + c = a ⎛ ⎝ x + \frac{b}{2 a} + \frac{1}{2} \sqrt{{(\frac{b}{a})}^{2} - 4 (\frac{c}{a})} ⎞ ⎠ ⎛ ⎝ x + \frac{b}{2 a} - \frac{1}{2} \sqrt{{(\frac{b}{a})}^{2} - 4 (\frac{c}{a})} ⎞ ⎠$ $ax^2+bx+c=a(x+b/(2a)+1/2sqrt((b/a)^2-4(c/a)))(x+b/(2a)-1/2sqrt((b/a)^2-4(c/a)))$

or

$a x^{2} + b x + c = a (x + \frac{b}{2 a} + \frac{1}{2 | a |} \sqrt{b^{2} - 4 a c}) (x + \frac{b}{2 a} - \frac{1}{2 | a |} \sqrt{b^{2} - 4 a c})$ $ax^2+bx+c=a(x+b/(2a)+1/(2absa)sqrt(b^2-4ac))(x+b/(2a)-1/(2absa)sqrt(b^2-4ac))$

Science

Math

Humanities

... and beyond

Question #3828f

1 Answer

Explanation:

Related questions

Impact of this question