How do you use the sum of two squares formula to solve 4x^2 -8=04x2−8=0?

1 Answer
Gió
May 12, 2015

I am not sure that this is what you want, but...
Considering: (a^2-b^2)=(a+b)(a-b)(a2−b2)=(a+b)(a−b)
Write:
4x^2-8=04x2−8=0
As:
(2x+sqrt(8))(2x-sqrt(8))=0(2x+√8)(2x−√8)=0

So:
(2x+sqrt(8))=0(2x+√8)=0
(2x-sqrt(8))=0(2x−√8)=0
x_1=-sqrt(8)/2x1=−√82
x_2=sqrt(8)/2x2=√82

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