How do you factor $y = 8 x^{3} + 9 x^{5} - 27 x^{2}$ $y=8x^3+9x^5-27x^2$ ?

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Answer 1 · 2018-07-09T23:49:48

$y = x^{2} (9 x^{3} + 8 x - 27)$ $y=x^2(9x^3+8x-27)$

Factor:

$y = 8 x^{3} + 9 x^{5} - 27 x^{2}$ $y=8x^3+9x^5-27x^2$

The GCF is $x^{2}$ $x^2$ . Factor out $x^{2}$ $x^2$ .

$y = x^{2} (9 x^{3} + 8 x - 27)$ $y=x^2(9x^3+8x-27)$

How do you factor y=8x^3+9x^5-27x^2 y=8x3+9x5−27x2y=8x^3+9x^5-27x^2 ?