How do you factor # 128^3 - 1024#? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Alan P. Jan 5, 2016 #128^3-1024 = color(green)(2^10(2^11-1))# Explanation: #128 = 2^7# #rarr 128^3 = 2^21# #1024 = 2^10# Therefore: #128^3-1024# #color(white)("XXX")=2^21-2^10# #color(white)("XXX")=2^10(2^11-1)# Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 1670 views around the world You can reuse this answer Creative Commons License