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How do you factor #16x^4-81 #?

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1 Answer

Jun 10, 2016

#(4x^2+9)(2x+3)(2x-3) #

Explanation:

#16 x^4 -81 = (4x^2)^2 -(3^2) = (4x^2 +9)(4x^2-9) =(4x^2+9)(2x+3)(2x-3) # [Ans]

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