How do you factor $y^3-64$ ?

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Answer 1 · 2016-01-30T03:11:02

$y^3-4^3=(y-4)(y^2+4y+16)$

$y^3-64$ is a difference of cubes, $a^3– b^3 = (a – b)(a^2 + ab + b^2)$ , where $a=y$ and $b=4$ .

Rewrite the equation.

$(y)^3-(4)^3=(y-4)(y^2+(y*4)+4^2)$

Simplify.

$y^3-4^3=(y-4)(y^2+4y+16)$

How do you factor y^3-64y^3-64?