How do you factor $p^{2} q^{2} - 12 p q + 36$ $p^2q^2-12pq+36$ ?

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How do you factor $p^{2} q^{2} - 12 p q + 36$ $p^2q^2-12pq+36$ ?

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Answer 1 · 2017-04-14T02:34:27

$p^{2} q^{2} - 12 p q + 36 = (p q - 6) (p q - 6)$ $p^2q^2-12pq+36 = (pq - 6)(pq - 6)$

Explanation:

Given: $p^{2} q^{2} - 12 p q + 36$ $p^2q^2-12pq+36$

This can be factored directly when we treat $p q$ $pq$ as a single variable that can be broken down later into two terms when their relationship is defined. To answer the question, solve for $p q$ $pq$ .

Looking at the expression, we see there will be two sets of brackets because of the $p^{2} q^{2}$ $p^2q^2$ and there will be two $-$ $-$ signs due to the $+ 36$ $+36$ and the $- 12$ $-12$ .

$p^{2} q^{2} - 12 p q + 36 = (p q - 6) (p q - 6)$ $p^2q^2-12pq+36 = (pq - 6)(pq - 6)$

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How do you factor $p^{2} q^{2} - 12 p q + 36$ $p^2q^2-12pq+36$ ?

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How do you factor $p^{2} q^{2} - 12 p q + 36$ $p^2q^2-12pq+36$ ?