Question #f4df0 Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Anjali G Nov 15, 2016 =(2x-1)(2x-1)=(2x−1)(2x−1) Explanation: 4x^2-4x+14x2−4x+1 =4x^2-2x-2x+1=4x2−2x−2x+1 =2x(2x-1)-(2x-1)=2x(2x−1)−(2x−1) =(2x-1)(2x-1)=(2x−1)(2x−1) Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor x^3 -8x3−8? What are the factors of x^3y^6 – 64? How do you know if x^2 + 10x + 25 is a perfect square? How do you write 16x^2 – 48x + 36 as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor 16x^2-36 using the difference of squares? How do you factor 2x^4y^2-32? How do you factor x^2 - 27? See all questions in Factor Polynomials Using Special Products Impact of this question 1294 views around the world You can reuse this answer Creative Commons License