How do you factor $64 v^{2} - 81$ $64v^2-81$ ?

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Answer 1 · 2015-05-07T19:08:34

$64 v^{2} - 81$ $64v^2-81$

$= {(8 v)}^{2} - {(9)}^{2}$ $= (8v)^2 -(9)^2$

$= (8 v + 9) (8 v - 9)$ $= (8v+9)(8v-9)$ by the difference of squares formula

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