How do you factor $p^2+4p+4-q^2$ ?

Question

2911 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-31T16:53:54

$(p+2+q)(p+2-q)$

$p^2+4p+4-q^2$
$=(p+2)^2-q^2$
Since $a^2-b^2-(a+b)(a-b)$
Similarly the above equation $=(p+2)^2-q^2$ can be written as
$(p+2+q)(p+2-q)$

How do you factor p^2+4p+4-q^2p^2+4p+4-q^2?