How do you factor $4 a^{2} - 25$ $4a^2-25$ ?

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Answer 1 · 2017-06-19T16:40:48

See a solution process below:

This is a special form of the quadratic:

$(x + y) (x - y) = x^{2} - y^{2}$ $(x + y)(x - y) = x^2 - y^2$

Substitute:

$2 a$ $2a$ for $x$ $x$

$5$ $5$ for $y$ $y$

Giving:

$(2 a + 5) (2 a - 5) = {(2 a)}^{2} - 5^{2}$ $(2a + 5)(2a - 5) = (2a)^2 - 5^2$

$(2 a + 5) (2 a - 5) = 4 a^{2} - 25$ $(2a + 5)(2a - 5) = 4a^2 - 25$

How do you factor 4a^2-254a2−254a^2-25?