How do you factor 3r^3-192r?

1 Answer
Jan 4, 2017

3r(r-8)(r+8)

Explanation:

The first step is to take out a color(blue)"common factor" of 3r

rArr3r(r^2-64)

We now have a color(blue)"difference of squares" inside the bracket, which factorises in general as.

color(red)(bar(ul(|color(white)(2/2)color(black)(a^2-b^2=(a-b)(a+b))color(white)(2/2)|)))

"here " a = r" and " b=8

rArrr^2-64=(r-8)(r+8)

"Pulling it all together gives"

3r^3-192r=3r(r-8)(r+8)