How do you factor 3r^3-192r?
1 Answer
Jan 4, 2017
Explanation:
The first step is to take out a
color(blue)"common factor" of 3r
rArr3r(r^2-64) We now have a
color(blue)"difference of squares" inside the bracket, which factorises in general as.
color(red)(bar(ul(|color(white)(2/2)color(black)(a^2-b^2=(a-b)(a+b))color(white)(2/2)|)))
"here " a = r" and " b=8
rArrr^2-64=(r-8)(r+8)
"Pulling it all together gives"
3r^3-192r=3r(r-8)(r+8)