How do you factor (x- 4)^3 -27(x−4)3−27?

1 Answer
Bdub
Mar 1, 2016

(x-4)^3-3^3=((x-4)-3)((x-4)^2+3(x-4)+9)=(x-7)(x^2-8x+16+3x-12+9)=(x-7)(x^2-5x+13)(x−4)3−33=((x−4)−3)((x−4)2+3(x−4)+9)=(x−7)(x2−8x+16+3x−12+9)=(x−7)(x2−5x+13)

Explanation:

This is a difference of 2 cubes so to factor use the formula x^3-y^3=(x-y)(x^2+xy+y^2)x3−y3=(x−y)(x2+xy+y2) and then simplify

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