How do you factor 64x^3-125? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Konstantinos Michailidis May 28, 2016 It is 64x^3-125=(4x)^3-5^3=(4 x-5) (16 x^2+20 x+25) Footnote We used the identity a^3-b^3=(a-b)(a^2+ab+b^2) where a=4x and b=5 Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor x^3 -8? What are the factors of x^3y^6 – 64? How do you know if x^2 + 10x + 25 is a perfect square? How do you write 16x^2 – 48x + 36 as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor 16x^2-36 using the difference of squares? How do you factor 2x^4y^2-32? How do you factor x^2 - 27? See all questions in Factor Polynomials Using Special Products Impact of this question 12053 views around the world You can reuse this answer Creative Commons License