How do you factor $49x^2 - 121y^2$ ?

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Answer 1 · 2015-05-04T07:20:47

$49x^2 - 121y^2$ can be written as $(7x)^2 - (11y)^2$

this is of the form:

$a^2 - b^2 = ( a + b) (a -b )$

here: $a = 7x$ and $b = 11y$

so ,

$(7x)^2 - (11y)^2= (7x+11y) (7x- 11y)$

the factorized form of $49x^2 - 121y^2$ is:

$(7x+11y) (7x- 11y)$

How do you factor 49x^2 - 121y^249x^2 - 121y^2?