Question

How do you rationalize the denominator and simplify `6/(sqrt(2x))`?

Answer 1

`[3sqrt(2x)]/x`

Explanation:

`6/(sqrt(2x))`
`6/(sqrt(2x))*[(cancel-sqrt(2x))/(cancel(-)sqrt(2x))]`
which will give,
`(cancel(6)sqrt(2x))/(cancel(2)x)=[3sqrt(2x)]/x`

Answer 2

`(3sqrt(2x))/x`

Explanation:

`"note that "sqrtaxxsqrta=a`

`"to rationalise the denominator, that is eliminate the"`
`"radical from the denominator then"`

`"multiply numerator/denominator by "sqrt(2x)`

`rArr6/(sqrt(2x))xxsqrt(2x)/sqrt(2x)`

`=(6sqrt(2x))/(2x)=(3sqrt(2x))/x`