How do you solve #4v - 35= - 8v#?

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Answer 1 · 2018-04-17T08:51:18

#v=35/12#

#4v-35=-8v#

Add #8v# to both sides

#4v+8v-35=0#

#12v-35=0#

Add 35 to both sides

#12v=35#

Divide both sides by 12

#v=35/12#

Answer 2 · 2018-04-17T08:52:33

#color(maroon)(v = 35 / 12 = 2 (11/12)#

$4v - 35 = -8v#

#4v + 8v - 35 = cancel(-8v) +cancel( 8v), " Adding 8v to both sides"#

#12v cancel(- 35) + cancel(35) = + 35, " Adding 35 to both sides"#

#12v = 35#

#color(maroon)(v = 35 / 12 = 2 (11/12)#