What is the quadratic formula of $0 = 10 x^{2} + 9 x - 1$ $0=10x^2 + 9x-1$ ?

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What is the quadratic formula of $0 = 10 x^{2} + 9 x - 1$ $0=10x^2 + 9x-1$ ?

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Answer 1 · 2018-04-25T04:49:03

$\frac{- 9 \pm \sqrt{81 - 4 (10) (- 1)}}{20}$ $(-9+-sqrt(81-4(10)(-1)))/20$

Explanation:

The equation given is in $a x^{2} + b x + c$ $ax^2+bx+c$ form. The general form for the quadratic formula of an unfactorable equation is:
$\frac{- b \pm \sqrt{b^{2} - 4 (a) (c)}}{2 a}$ $(-b+-sqrt(b^2-4(a)(c)))/(2a)$
just take the terms and plug them in, you should get the correct answer.

Answer 2 · 2018-04-25T04:49:25

$x = \frac{- 9 \pm \sqrt{9^{2} - 4 (10) (- 1)}}{2 (10)}$ $x=(-9+-sqrt(9^2-4(10)(-1)))/(2(10))$

Explanation:

The Quadratic Formula is $x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$ $x=(-b+-sqrt(b^2-4ac))/(2a)$

The equation $10 x^{2} + 9 x - 1$ $10x^2+9x-1$ is in standard form, which is $a x^{2} + b x + c$ $ax^2+bx+c$ . We can replace the letters in the quadratic formula with the letters from the equation.

$x = \frac{- 9 \pm \sqrt{9^{2} - 4 (10) (- 1)}}{2 (10)}$ $x=(-9+-sqrt(9^2-4(10)(-1)))/(2(10))$

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What is the quadratic formula of $0 = 10 x^{2} + 9 x - 1$ $0=10x^2 + 9x-1$ ?

2 Answers

Explanation:

Explanation:

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What is the quadratic formula of $0 = 10 x^{2} + 9 x - 1$ $0=10x^2 + 9x-1$ ?