How do you solve #sqrt(x -1) = x - 3#?

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Answer 1 · 2018-04-25T23:15:24

x=2,5

To remove the square root, square both sides

#x-1=(x-3)^2#

Square the right side

#(x-3)^2=(x-3)(x-3)=x^2-3x-3x+9#

#x-1=x^2-6x+9#

Combine terms and set equation to 0

#0=x^2-7x+10#

Factor

#0=(x-2)(x-5)#