How do you solve x^2 + 2x + 10 = 0 using the quadratic formula?

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Answer 1 · 2018-04-30T22:11:35

$- 1 \pm 3 i$ $-1 +- 3i$

Our equation is $x^{2} + 2 x + 10 = 0$ $x^2 +2x +10 = 0$ a = 1, b = 2, c = 10.

Now, using the quadratic formula $\frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$ $(-b +- sqrt(b^2 - 4ac))/(2a)$ , we just plug in our values:

$\frac{- 2 \pm \sqrt{2^{2} - (4 \cdot 1 \cdot 10)}}{2 \cdot 1}$ $(-2 +- sqrt(2^2 -(4 * 1 * 10)))/(2 * 1)$

Now simplify.

$\frac{- 2 \pm \sqrt{4 - 40}}{2}$ $(-2 +- sqrt(4 - 40))/(2)$

$\frac{- 2 \pm \sqrt{- 36}}{2}$ $(-2 +- sqrt(-36))/2$

$\frac{- 2 \pm 6 i}{2}$ $(-2 +- 6i)/2$

$- 1 \pm 3 i$ $-1 +- 3i$