How do you simplify $\frac{1 + 2 \sqrt{3}}{1 + \sqrt{3}}$ $(1 + 2 sqrt3) /( 1 + sqrt3 )$ ?

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How do you simplify $\frac{1 + 2 \sqrt{3}}{1 + \sqrt{3}}$ $(1 + 2 sqrt3) /( 1 + sqrt3 )$ ?

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Answer 1 · 2018-05-02T01:02:02

$\frac{7}{4}$ $7/4$

Explanation:

To start, you want to get rid of both square roots.
To do this you want to multiply $\sqrt[2]{3}$ $root2(3)$ to the nominator and the denominator of the equation.
$\frac{1 + 2 \sqrt[2]{3} \times \sqrt[2]{3}}{1 + \sqrt[2]{3} \times \sqrt[2]{3}}$ $(1+2root2(3) times root2(3))/(1+root2(3) times root2(3))$
Doing this will cancel out the roots and make the $\sqrt[2]{3}$ $root2(3)$ become a $3$ $3$ .
$\frac{1 + 2 \times 3}{1 + 3}$ $(1+2 times 3)/(1+3)$
From this point on you just follow BEDMAS and solve the equation.
$\frac{7}{4}$ $7/4$
All done!

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How do you simplify $\frac{1 + 2 \sqrt{3}}{1 + \sqrt{3}}$ $(1 + 2 sqrt3) /( 1 + sqrt3 )$ ?

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How do you simplify (1 + 2 sqrt3) /( 1 + sqrt3 )1+2√31+√3(1 + 2 sqrt3) /( 1 + sqrt3 )?

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How do you simplify $\frac{1 + 2 \sqrt{3}}{1 + \sqrt{3}}$ $(1 + 2 sqrt3) /( 1 + sqrt3 )$ ?