Question

How do you find the product of `(3a-b)(2a-b)`?

Answer 1

Multiply each term in the parenthesis by each term in the other parenthesis, or better known as the FOIL method.

Explanation:

`(3a-b) (2a-b)`

`= (3a)(2a)+ (3a)(-b)+(-b)(2a)+(-b)(-b)`

`= 6a^2 + b^2 - 5ab`

Answer 2

Formally, `(a + b) * (c + d) = ac + ad + bc + bd`.
When there are negative signs or subtraction involved, it may be helpful to re-write the equation in standard form.

Explanation:

`(3a - b)(2a - b) =`
`(3a + -b)(2a + -b)=`
`(3a * 2a) + (3a * -b) + (-b * 2a) + (-b * -b) =`
`6a^2 + (-3ab) + (-2ab) + (b^2)=`
`6a^2 -5ab + b^2`

Answer 3

Please read below:

Explanation:

Consider making a table to list all the available terms in the binomials.

When you're multiplying binomials, you're multiplying each term of one binomial, with one of the other.

`3a times -b; 3a times 2a`
`-b times 2a; -b times -b`

This should get you `6a^2-5ab+b^2` as your product.