How do you simplify $\sqrt{21} \cdot \sqrt{24}$ $sqrt21*sqrt24$ ?

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How do you simplify $\sqrt{21} \cdot \sqrt{24}$ $sqrt21*sqrt24$ ?

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Answer 1 · 2018-05-06T09:40:25

$\sqrt{21} \cdot \sqrt{24} = 6 \cdot \sqrt{14}$ $\sqrt(21)*\sqrt(24)=6*\sqrt(14)$

Explanation:

$\sqrt{21} \cdot \sqrt{24} =$ $\sqrt(21)*\sqrt(24)=$
$= \sqrt{21 \cdot 24} = \sqrt{3 \cdot 7 \cdot 3 \cdot 8} = \sqrt{3^{2} \cdot 7 \cdot 2 \cdot 2^{2}} =$ $=\sqrt(21*24)=\sqrt(3*7*3*8)=\sqrt(3^2*7*2*2^2)=$
$= 3 \cdot 2 \cdot \sqrt{2 \cdot 7} = 6 \cdot \sqrt{14}$ $=3*2*\sqrt(2*7)=6*\sqrt(14)$

Answer 2 · 2018-05-06T09:48:55

$6 \sqrt{14}$ $6sqrt14$

Explanation:

$using the law of radicals$ $"using the "color(blue)"law of radicals"$

$∙ x \sqrt{a} \times \sqrt{b} \Leftrightarrow \sqrt{a b}$ $•color(white)(x)sqrtaxxsqrtbhArrsqrt(ab)$

$simplifying \sqrt{24} = \sqrt{4 \times 6} = \sqrt{4} \times \sqrt{6} = 2 \sqrt{6}$ $"simplifying "sqrt24=sqrt(4xx6)=sqrt4xxsqrt6=2sqrt6$

$\Rightarrow \sqrt{21} \times 2 \sqrt{6} = 2 \sqrt{126}$ $rArrsqrt21xx2sqrt6=2sqrt126$

$= 2 \sqrt{9 \times 14} = 2 (\sqrt{9} \times \sqrt{14}) = 2 (3 \sqrt{14}) = 6 \sqrt{14}$ $=2sqrt(9xx14)=2(sqrt9xxsqrt14)=2(3sqrt14)=6sqrt14$

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How do you simplify $\sqrt{21} \cdot \sqrt{24}$ $sqrt21*sqrt24$ ?

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