How do you foil #4 (3x+1) (x-2)#?

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Answer 1 · 2018-05-08T17:34:03

#12x^2-20x-8#

First, distribute the #4# to the #(3x+1)#:
#4*3x=12x#
#4*1=4#

Then, use FOIL to multiply #(12x+4)(x-2)#:

First: #12x*x = 12x^2#

Outer: #12x*-2 = -24x#

Inner: #4*x = 4x#

Last: #4*-2 = -8#

Your expression is now:

#12x^2-24x+4x-8#

and you can combine #-24x+4x#, as they are like terms, to get a final answer of:

#12x^2-20x-8#