How do you simplify $\frac{1}{\sqrt{a} + \sqrt{b}}$ $1/(sqrta+sqrtb)$ ?

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How do you simplify $\frac{1}{\sqrt{a} + \sqrt{b}}$ $1/(sqrta+sqrtb)$ ?

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Answer 1 · 2018-05-13T12:41:35

$\frac{\sqrt{a} - \sqrt{b}}{a - b}$ $(sqrta-sqrtb)/(a-b)$

Explanation:

Expression $= \frac{1}{\sqrt{x} + \sqrt{b}}$ $= 1/(sqrtx+sqrtb)$

Rationalise the denominator:

Expression $= \frac{1}{\sqrt{x} + \sqrt{b}} \times \frac{\sqrt{a} - \sqrt{b}}{\sqrt{a} - \sqrt{b}}$ $= 1/(sqrtx+sqrtb) xx (sqrta - sqrtb)/ (sqrta - sqrtb)$

$= \frac{\sqrt{a} - \sqrt{b}}{a - b}$ $= (sqrta-sqrtb)/(a-b)$

Answer 2 · 2018-05-13T12:42:45

On simplification it would be $\frac{\sqrt{a} - \sqrt{b}}{a - b}$ $(sqrta-sqrtb)/(a-b)$

Explanation:

We have
$\frac{1}{\sqrt{a} + \sqrt{b}}$ $1/(sqrta+sqrtb)$
Multiplying and diving by $\sqrt{a} - \sqrt{b}$ $sqrta-sqrtb$
We get $\frac{\sqrt{a} - \sqrt{b}}{a - b}$ $(sqrta-sqrtb)/(a-b)$ which is the possible simplest form.

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How do you simplify $\frac{1}{\sqrt{a} + \sqrt{b}}$ $1/(sqrta+sqrtb)$ ?

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Explanation:

Explanation:

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How do you simplify 1√a+√b1/(sqrta+sqrtb)?

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How do you simplify $\frac{1}{\sqrt{a} + \sqrt{b}}$ $1/(sqrta+sqrtb)$ ?