How do you find 2 number if the sum of two numbers is 22 and the first number is 10 less than 3 times the other number?

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Answer 1 · 2018-05-22T06:35:11

#14# and #8#

let the two numbers be #a# and #b#.

1) the sum of the two numbers is 22

#a+b=22#

2) the first number is 10 less than 3 times the other number:

#a=3b-10#

We can substitute the second expression into the first one to get the following expression and solve for b:

#a+b=22 -> (3b-10)+b=22#

#4b-10=22#
#4b=32#
#b=8#

Now since #a+b=22# and #b=8#, #a + 8 = 22# and therefore #a =14#

#a=14#, #b=8#