How do you evaluate ${(16^{\frac{1}{2}})}^{3}$ $(16^{\frac{1}{2}})^3$ ?

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How do you evaluate ${(16^{\frac{1}{2}})}^{3}$ $(16^{\frac{1}{2}})^3$ ?

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Answer 1 · 2018-05-25T02:35:59

You would multiply the exponents.

Explanation:

Because of the power of a power property, you would multiply $\frac{1}{2}$ $1/2$ and 3, giving you $\frac{3}{2}$ $3/2$ .
Now, you have $16^{\frac{2}{3}}$ $16^(2/3)$ or the cube root of $16^{2}$ $16^2$ . This equals to about 6.3496 if you plug it into a calculator.
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How do you evaluate ${(16^{\frac{1}{2}})}^{3}$ $(16^{\frac{1}{2}})^3$ ?

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How do you evaluate ${(16^{\frac{1}{2}})}^{3}$ $(16^{\frac{1}{2}})^3$ ?