In a $DeltaABC$ , $b=10m$ , $c=21m$ and $/_A=58^o$ . What is the area of the triangle?

Question

(a) $105$ $m^2$
(b) $55.64$ $m^2$
(c) $82.02$ $m^2$
(d) $89.05$ $m^2$

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Answer 1 · 2016-06-26T17:18:38

(d) $89.05$ .

As $b=10m$ , $c=21m$ and $/_A=58^o$

Area of the triangle is given by

$1/2xxbxxcxxsinA$

= $1/2xx10xx21xxsin58^o$

= $1/2xx10xx21xx0.84805$

= $5xx21xx0.848=89.05$ $m^2$

Hence answer is (d) $89.05$ .