Question #3b6b1

1 Answer
Martin C.
Feb 28, 2018

y'=ABCe^(-Bt)(1+Ae^(-Bt))^-2

Explanation:

I suppose that t is the variable which should be differentiated...

y=C/(1+Ae^(-Bt) )=C(1+Ae^(-Bt))^-1
y=C*(u)^-1
u=1+Ae^(-Bt)
y'=-C*u'*(u)^-2
u'=-ABe^(-Bt)
y'=ABCe^(-Bt)(1+Ae^(-Bt))^-2

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