Question #70242

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Answer 1 · 2016-10-04T04:12:56

After applying the Product Rule your answer should be

$y'= sec^3(x)+tan^2(x)sec(x)$

$y=uv$

You have to apply the Product Rule

$y'= uv'+u'v$

$u=sec(x)$
$u'= sec(x) tan(x)$

$v=tan(x)$
$v'=sec^2(x)$

$y'= sec(x)sec^2(x)+tan(x)sec(x)tan(x)$

Simplified

$y'= sec^3(x)+tan^2(x)sec(x)$