Question #2ef3f

Oct 10, 2016

$f'(x)=3sin^2xcosx-3cosx = -3cos^3x$

Use the chain rule to differentiate $sin^3 x = (sinx)^3$

$f'(x)=3sin^2xcosx-3cosx$ which can be rewritten

$= 3cosx(sin^2x-1)$

$= -3cosx(1-sin^2x)$

$= -3cosx(cos^2x)$

$= -3cos^3x$

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