Question #feb84

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Answer 1 · 2016-10-26T16:25:43

$11 (x - 2) + (x - 5) = (x + 2) (x - 6)$ $11(x-2)+(x-5)=(x+2)(x-6)$

$\Rightarrow 11 x - 22 + x - 5 = x^{2} - 4 x - 12$ $=>11x-22+x-5=x^2-4x-12$

$\Rightarrow x^{2} - 4 x - 12 - 12 x + 27 = 0$ $=>x^2-4x-12-12x+27=0$

$\Rightarrow x^{2} - 16 x + 15 = 0$ $=>x^2-16x+15=0$

$\Rightarrow x^{2} - 15 x - x + 15 = 0$ $=>x^2-15x-x+15=0$

$\Rightarrow x (x - 15) - 1 (x - 15) = 0$ $=>x(x-15)-1(x-15)=0$

$\Rightarrow (x - 15) (x - 1) = 0$ $=>(x-15)(x-1)=0$

$x = 15 and x = 1$ $x=15 and x=1$