Question #c2483

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Question #c2483

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Answer 1 · 2016-11-03T05:29:12

$- 2 x^{4} \cdot 7 x^{4} = - 14 x^{8}$ $-2x^4*7x^4=-14x^8$

Explanation:

Using the commutative and associative properties of multiplication along with the property of exponents that $x^{a} \cdot x^{b} = x^{a + b}$ $x^a*x^b = x^(a+b)$ , we have

$- 2 x^{4} \cdot 7 x^{4} = (- 2 \cdot 7) (x^{4} \cdot x^{4})$ $-2x^4*7x^4 = (-2*7)(x^4*x^4)$

$= (- 14) (x^{4 + 4})$ $=(-14)(x^(4+4))$

$= - 14 x^{8}$ $=-14x^8$

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Question #c2483

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