Question #4eef0

1 Answer
Jan 11, 2017

1+sec(sqrt(x))

Explanation:

In a define integral where one of the limits is a variable it is poor notation to use the same variable as the variable of integration, so I will write

int_pi^sqrt(x) \ sec(x)tan(x) \ dx as int_pi^sqrt(x) \ sec(t)tan(t) \ dt

We use the known result

d/dxsecx = secxtanx

This gives us (without the need for a substitution):

int_pi^sqrt(x) \ sec(t)tan(t) \ dt = [sect]_pi^sqrt(x)
" " = sec(sqrt(x)) - sec(pi)
" " = sec(sqrt(x)) - (-1)
" " = 1+sec(sqrt(x))