Question #4eef0
1 Answer
Jan 11, 2017
1+sec(sqrt(x))
Explanation:
In a define integral where one of the limits is a variable it is poor notation to use the same variable as the variable of integration, so I will write
int_pi^sqrt(x) \ sec(x)tan(x) \ dx asint_pi^sqrt(x) \ sec(t)tan(t) \ dt
We use the known result
d/dxsecx = secxtanx
This gives us (without the need for a substitution):
int_pi^sqrt(x) \ sec(t)tan(t) \ dt = [sect]_pi^sqrt(x)
" " = sec(sqrt(x)) - sec(pi)
" " = sec(sqrt(x)) - (-1)
" " = 1+sec(sqrt(x))