Question #ead50

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Answer 1 · 2016-11-15T15:24:19

The point $(-4,0)$

$x$ intercept is when $y=0$

substitute $0$ instead of $y$ and then solve for $x$

$-3x+8(0)=12$
$-3x=12$
$x=-4$

The point is $(-4,0)$

Answer 2 · 2016-11-15T15:25:44

The x-intercept= -4
$(-4,0)$

To find the x-intercept of a graph, make $y=0$

$-3x+8y = 12$

$-3x+8(0) = 12$

$-3x= 12" "larrdiv -3$

$x =-4$