Question #ada15

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Answer 1 · 2016-12-09T21:27:27

$x = - 2$ $x = -2$ and $y = - 3$ $y = -3$

Step 1) Solve the second equation for $x$ $x$ :

$x + y - y = - 5 - y$ $x + y - y = -5 - y$

$x + 0 = - 5 - y$ $x + 0 = -5 - y$

$x = - 5 - y$ $x = -5 - y$

Step 2) Substitute $- 5 - y$ $-5 - y$ for $x$ $x$ in the first equation and solve for $y$ $y$ :

$3 (- 5 - y) - 2 y = 0$ $3(-5 - y) - 2y = 0$

$- 15 - 3 y - 2 y = 0$ $-15 - 3y - 2y = 0$

$15 - 15 - 5 y = 0 + 15$ $15 - 15 - 5y = 0 + 15$

$0 - 5 y = 15$ $0 - 5y = 15$

$- 5 y = 15$ $-5y = 15$

$\frac{- 5 y}{- 5} = \frac{15}{- 5}$ $(-5y)/(-5) = 15/(-5)$

$y = - 3$ $y = -3$

Now substitute $- 3$ $-3$ for $y$ $y$ in the solution to the second equation in Step 1) and calculate $x$ $x$ .

$x = - 5 - (- 3)$ $x = -5 - (-3)$

$x = - 5 + 3$ $x = -5 + 3$

$x = - 2$ $x = -2$