Solve the equation ${(3 W)}^{2} = 2 W (4 W + 3)$ $(3W)^2=2W(4W+3)$ ?

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Answer 1 · 2017-02-02T05:02:50

$W = 0$ $W=0$ or $W = 6$ $W=6$

${(3 W)}^{2} = 2 W (4 W + 3)$ $(3W)^2=2W(4W+3)$ is equivalent to

$3 W \times 3 W = 2 W \times 4 W + 2 W \times 3$ $3Wxx3W=2Wxx4W+2Wxx3$

or $9 W^{2} = 8 W^{2} + 6 W$ $9W^2=8W^2+6W$

or $W^{2} - 6 W = 0$ $W^2-6W=0$

or $W (W - 6) = 0$ $W(W-6)=0$

Hence, either $W = 0$ $W=0$ or $W - 6 = 0$ $W-6=0$ i.e. $W = 6$ $W=6$

Solve the equation (3W)2=2W(4W+3)(3W)^2=2W(4W+3)?