What is $[HO^-]$ of a solution for which $pH=3.10$ ?

Question

2630 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-08T16:59:39

$[HO^-]=1.27xx10^-11*mol*L^-1$ .............

We use the relationship $14=pH+pOH$

Now $pH=-log_10(7.90xx10^-4)=-(-3.10)=3.10$

And $pOH=14-3.10=10.80$

And we can now take antilogarithms,

$[HO^-]=10^(-10.8)=1.27xx10^-11*mol*L^-1$

What is [HO^-][HO^-] of a solution for which pH=3.10pH=3.10?